Extracting Files from Zip Entry to Memory

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To extract a file from a zip to a memory variable (for instance, a Byte array), use the following function.

Make sure to add these using statements at the top of the code:

using C1.C1Zip;
using System.IO;

C#	Copy Code
private byte[] GetDataFromZipFile(string zipFileName, string entryName) { // Get the entry from the zip file. C1ZipFile zip = new C1ZipFile(); zip.Open(zipFileName); C1ZipEntry ze = zip.Entries[entryName]; // Copy the entry data into a memory stream. MemoryStream ms = new MemoryStream(); byte[] buf = new byte[1000]; using (Stream s = ze.OpenReader()) { for (;;) { int read = s.Read(buf, 0, buf.Length); if (read == 0) break; ms.Write(buf, 0, read); } } // There's no need to call close because of the C# 'using' // statement above but in VB this would be necessary. //s.Close(); // Return result. return ms.ToArray(); }

Copy Code

private byte[] GetDataFromZipFile(string zipFileName, string entryName)
{
    // Get the entry from the zip file.
    C1ZipFile zip = new C1ZipFile();
    zip.Open(zipFileName);
    C1ZipEntry ze = zip.Entries[entryName];
    // Copy the entry data into a memory stream.
    MemoryStream ms = new MemoryStream();
    byte[] buf = new byte[1000];
    using (Stream s = ze.OpenReader())
    {
        for (;;)
        {
            int read = s.Read(buf, 0, buf.Length);
            if (read == 0) break;
            ms.Write(buf, 0, read);
        }
    }
    // There's no need to call close because of the C# 'using'
    // statement above but in VB this would be necessary.
    //s.Close();
    // Return result.
    return ms.ToArray();
}

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