Create column of buttons in Flex Grid

Posted by: pablo on 8 November 2021, 8:11 pm EST

  • Posted 8 November 2021, 8:11 pm EST

    I have a question related to the Flex Grid and the cell template. I’m trying to create a button in each cell from a column, with the aim of showing a view. I’ve already done it, however, I need to bind a different value from the model in each cell. To explain myself, I have a model defined in the view (where I’m creating the Flex Grid) like this:

     @model IEnumerable<C1MvcApplication1.Models.Clients>

    And the Flex Grid is defined in this way:

    <c1-flex-grid id="theFlexGrid"
    <c1-flex-grid-column binding="clientCode" header="Code"></c1-flex-grid-column>
    <c1-flex-grid-column binding="clientName" header="Name" width="200"></c1-flex-grid-column>
    <c1-flex-grid-column is-read-only="false" align="center" width="70">
    <a id="edit" asp-controller="clients" asp-action="Edit" class="btn btn-default" asp-route-clientCode="xxxx" style="background-color:none;"><img src="~/lib/icons/Edit.png" /></a>
    <c1-items-source source-collection="@Model"></c1-items-source>

    In this example I have defined an asp-route-clientName with a single value “xxxx”. Nevertheless, what I’m trying to do is to define a value like “@Model.clientCode”. I know that’s something we can’t do with the type IEnumerable<> but I need a solution to select each value from this variable.
  • Marked as Answer

    Replied 9 November 2021, 7:06 pm EST


    Please refer to the following points for the resolution of the above query:

    * Instead of using an anchor tag, we may add a click event listener to the set template and may implement the following functionality in the handler.

    * To get the dataItem for the selected row, we may use the hitTest and dataItem property of FlexGrid Row, to get the required information.

    * After which we may redirect the user to the next view with the above information accordingly.

    Please refer to the sample below.

    Dushyant Sharma
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